The Problem
Your goal in this problem is to divide a certain integer n by another integer m until n = 1, obtaining a sequence of numbers. Lets call a[i] each number of this sequence, and let's say it has k numbers (i.e. you must do k-1 succesive divisions to reach n = 1). You can only have this sequence if the following restrictions are met:
- a[1] = n, a[i] = a[i-1] div m, for all 1 < i <= k
- a[i] is divisible by m (that is, a[i] mod m = 0) for all 1 <= i < k
- a[1] > a[2] > a[3] ... > a[k]
For instance, if n = 125 and m = 5, you have 125, 25, 5 and 1 (you did 3 divisions: 125/5, 25/5 and 5/5). So, k = 4, a[1] = 125, a[2] = 25, a[3] = 5 and a[4] = 1. If n = 30 and m = 3, you have 30, 10, 3 and 1. But a[2] = 10, and 10 mod 3 = 1, so there is no sequence because it violates restriction 2. When the sequence doesn't exist we think it's not fun and, thus, very boring!
The Input
The input will consist on an arbitrary number of lines. Each line will consist of two non-negative integers n,m which are both less than 2000000000. You must read until you reach the end of file.
The Output
For each pair n,m you must print the correpondent sequence a (as defined above) in a single line, with each adjacent numbers of the sequence separated by a single space. In the case the sequence doesn't exist because it violates some restriction, just print the phrase "Boring!" in a single line (without the quotes).
Sample Input
125 5
30 3
80 2
81 3
Sample Output
125 25 5 1
Boring!
Boring!
81 27 9 3 1
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class UVA10190 {
public static void main(String[] args) throws NumberFormatException,
IOException {
int n, m;
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String s = "";
StringTokenizer stk;
while ((s = in.readLine()) != null) {
StringBuilder sb = new StringBuilder();
stk = new StringTokenizer(s.trim());
n = Integer.parseInt(stk.nextToken());
m = Integer.parseInt(stk.nextToken());
sb.append(n);
int quo = n;
boolean isBoring = m < 2 || quo < 2;
while (!isBoring && quo > 1) {
if (quo % m != 0)
isBoring = true;
quo = quo / m;
sb.append(" " + quo);
}
if (isBoring) {
System.out.println("Boring!");
} else {
System.out.println(sb);
}
}
}
}
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