UVA10035

Problem B: Primary Arithmetic

Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the "carry" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.

Input

Each line of input contains two unsigned integers less than 10 digits. The last line of input contains 0 0.

Output

For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.

Sample Input

123 456
555 555
123 594
0 0

Sample Output

No carry operation.
3 carry operations.
1 carry operation.

大意: 給2個小於10位的整數 求兩者相加後會有多少進位

解法:

儲存進位值 一位一位往前推

import java.util.*;

public class UVA10035 {

 public static void main(String[] args) {

  Scanner sc = new Scanner(System.in);

  while (sc.hasNext()) {
   int N = sc.nextInt();

   int M = sc.nextInt();

   int carry = 0, c = 0;

   if (N == 0 && M == 0)
    break;

   while (N > 0 || M > 0) {
    c = (N % 10 + M % 10 + c) > 9 ? 1 : 0;

    carry += c;

    N /= 10;
    M /= 10;

   }
   if (carry == 0)
    System.out.println("No carry operation.");

   else if (carry == 1)

    System.out.println("1 carry operation.");

   else
    System.out.println(carry + " carry operations.");

  }

  sc.close();
 }

}